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1 # Copyright 2004-2005 Elemental Security, Inc. All Rights Reserved.
2 # Licensed to PSF under a Contributor Agreement.
3
4 """Safely evaluate Python string literals without using eval()."""
5
6 import re
7 from typing import Dict, Match
8
9 simple_escapes: Dict[str, str] = {
10 "a": "\a",
11 "b": "\b",
12 "f": "\f",
13 "n": "\n",
14 "r": "\r",
15 "t": "\t",
16 "v": "\v",
17 "'": "'",
18 '"': '"',
19 "\\": "\\",
20 }
21
22
23 def escape(m: Match[str]) -> str:
24 all, tail = m.group(0, 1)
25 assert all.startswith("\\")
26 esc = simple_escapes.get(tail)
27 if esc is not None:
28 return esc
29 if tail.startswith("x"):
30 hexes = tail[1:]
31 if len(hexes) < 2:
32 raise ValueError("invalid hex string escape ('\\%s')" % tail)
33 try:
34 i = int(hexes, 16)
35 except ValueError:
36 raise ValueError("invalid hex string escape ('\\%s')" % tail) from None
37 else:
38 try:
39 i = int(tail, 8)
40 except ValueError:
41 raise ValueError("invalid octal string escape ('\\%s')" % tail) from None
42 return chr(i)
43
44
45 def evalString(s: str) -> str:
46 assert s.startswith("'") or s.startswith('"'), repr(s[:1])
47 q = s[0]
48 if s[:3] == q * 3:
49 q = q * 3
50 assert s.endswith(q), repr(s[-len(q) :])
51 assert len(s) >= 2 * len(q)
52 s = s[len(q) : -len(q)]
53 return re.sub(r"\\(\'|\"|\\|[abfnrtv]|x.{0,2}|[0-7]{1,3})", escape, s)
54
55
56 def test() -> None:
57 for i in range(256):
58 c = chr(i)
59 s = repr(c)
60 e = evalString(s)
61 if e != c:
62 print(i, c, s, e)
63
64
65 if __name__ == "__main__":
66 test()